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Change a parameter name from format to file_format

pull/1640/head
Hironsan 3 years ago
parent
commit
a090e94d0f
2 changed files with 4 additions and 4 deletions
  1. 4
      backend/data_import/celery_tasks.py
  2. 4
      backend/data_import/views.py

4
backend/data_import/celery_tasks.py

@ -10,11 +10,11 @@ from .pipeline.writers import BulkWriter
@shared_task
def ingest_data(user_id, project_id, filenames, format: str, **kwargs):
def ingest_data(user_id, project_id, filenames, file_format: str, **kwargs):
project = get_object_or_404(Project, pk=project_id)
user = get_object_or_404(get_user_model(), pk=user_id)
parser = create_parser(format, **kwargs)
parser = create_parser(file_format, **kwargs)
builder = create_bulder(project, **kwargs)
reader = Reader(filenames=filenames, parser=parser, builder=builder)
cleaner = create_cleaner(project)

4
backend/data_import/views.py

@ -31,7 +31,7 @@ class UploadAPI(APIView):
def post(self, request, *args, **kwargs):
project_id = self.kwargs['project_id']
upload_ids = request.data.pop('uploadIds')
format = request.data.pop('format')
file_format = request.data.pop('format')
tus = [TemporaryUpload.objects.get(upload_id=upload_id) for upload_id in upload_ids]
sus = [
@ -46,7 +46,7 @@ class UploadAPI(APIView):
user_id=request.user.id,
project_id=project_id,
filenames=filenames,
format=format,
file_format=file_format,
**request.data
)
return Response({'task_id': task.task_id})
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